Kimberly had 48 less jelly beans than Kylie. Kylie used
67 of her jelly beans and Kimberly used
34 of her jelly beans. In the end, Kylie had 4 times as much as Kimberly. Find the number of jelly beans that Kylie had at first.
| |
Kylie |
Kimberly |
Comparing Kylie
and Parry at first |
|
48 less |
| Before |
7x4 =
28 u |
4 u |
| Change |
- 6x4 =
- 24 u |
- 3 u |
| After |
1x4 =
4 u |
1 u |
Comparing Kylie
and Parry in the end |
4 u |
1 u |
The number of jelly beans that Kylie had in the end is repeated. Make the number of jelly beans that Kylie had in the end the same. LCM of 1 and 4 is 4.
Number of jelly beans that Kimberly had less than Kylie
= 28 u - 4 u
= 24 u
24 u = 48
1 u = 48 ÷ 24 = 2
Number of jelly beans that Kylie had at first
= 28 u
= 28 x 2
= 56
Answer(s): 56
