Joelle had 55 less jelly beans than Jade. Jade used
34 of her jelly beans and Joelle used
45 of her jelly beans. In the end, Jade had 4 times as much as Joelle. Find the number of jelly beans that Jade had at first.
| |
Jade |
Joelle |
Comparing Jade
and Parry at first |
|
55 less |
| Before |
4x4 =
16 u |
5 u |
| Change |
- 3x4 =
- 12 u |
- 4 u |
| After |
1x4 =
4 u |
1 u |
Comparing Jade
and Parry in the end |
4 u |
1 u |
The number of jelly beans that Jade had in the end is repeated. Make the number of jelly beans that Jade had in the end the same. LCM of 1 and 4 is 4.
Number of jelly beans that Joelle had less than Jade
= 16 u - 5 u
= 11 u
11 u = 55
1 u = 55 ÷ 11 = 5
Number of jelly beans that Jade had at first
= 16 u
= 16 x 5
= 80
Answer(s): 80
