Wendy had 126 more jelly beans than Xylia. Wendy used
45 of her jelly beans and Xylia used
12 of her jelly beans. In the end, Wendy had 4 times as much as Xylia. Find the number of jelly beans that Xylia had at first.
| |
Wendy |
Xylia |
Comparing Wendy
and Parry at first |
126 more |
|
| Before |
5x4 =
20 u |
2 u |
| Change |
- 4x4 =
- 16 u |
- 1 u |
| After |
1x4 =
4 u |
1 u |
Comparing Wendy
and Parry in the end |
4 u |
1 u |
The number of jelly beans that Wendy had in the end is repeated. Make the number of jelly beans that Wendy had in the end the same. LCM of 1 and 4 is 4.
Number of jelly beans that Wendy had more than Xylia
= 20 u - 2 u
= 18 u
18 u = 126
1 u = 126 ÷ 18 = 7
Number of jelly beans that Xylia had at first
= 2 u
= 2 x 7
= 14
Answer(s): 14
