Roshel had 84 less chocolate bars than Abi. Abi used
56 of her chocolate bars and Roshel used
45 of her chocolate bars. In the end, Abi had 2 times as much as Roshel. Find the number of chocolate bars that Abi had at first.
|
Abi |
Roshel |
Comparing Abi and Parry at first |
|
84 less |
Before |
6x2 = 12 u |
5 u |
Change |
- 5x2 = - 10 u |
- 4 u |
After |
1x2 = 2 u |
1 u |
Comparing Abi and Parry in the end |
2 u |
1 u |
The number of chocolate bars that Abi had in the end is repeated. Make the number of chocolate bars that Abi had in the end the same. LCM of 1 and 2 is 2.
Number of chocolate bars that Roshel had less than Abi
= 12 u - 5 u
= 7 u
7 u = 84
1 u = 84 ÷ 7 = 12
Number of chocolate bars that Abi had at first
= 12 u
= 12 x 12
= 144
Answer(s): 144