Marion had 72 more jelly beans than Shannon. Marion used
45 of her jelly beans and Shannon used
23 of her jelly beans. In the end, Marion had 3 times as much as Shannon. Find the number of jelly beans that Shannon had at first.
| |
Marion |
Shannon |
Comparing Marion
and Parry at first |
72 more |
|
| Before |
5x3 =
15 u |
3 u |
| Change |
- 4x3 =
- 12 u |
- 2 u |
| After |
1x3 =
3 u |
1 u |
Comparing Marion
and Parry in the end |
3 u |
1 u |
The number of jelly beans that Marion had in the end is repeated. Make the number of jelly beans that Marion had in the end the same. LCM of 1 and 3 is 3.
Number of jelly beans that Marion had more than Shannon
= 15 u - 3 u
= 12 u
12 u = 72
1 u = 72 ÷ 12 = 6
Number of jelly beans that Shannon had at first
= 3 u
= 3 x 6
= 18
Answer(s): 18
