Xylia had 24 less jelly beans than Jade. Jade used
56 of her jelly beans and Xylia used
34 of her jelly beans. In the end, Jade had 2 times as much as Xylia. Find the number of jelly beans that Jade had at first.
| |
Jade |
Xylia |
Comparing Jade
and Parry at first |
|
24 less |
| Before |
6x2 =
12 u |
4 u |
| Change |
- 5x2 =
- 10 u |
- 3 u |
| After |
1x2 =
2 u |
1 u |
Comparing Jade
and Parry in the end |
2 u |
1 u |
The number of jelly beans that Jade had in the end is repeated. Make the number of jelly beans that Jade had in the end the same. LCM of 1 and 2 is 2.
Number of jelly beans that Xylia had less than Jade
= 12 u - 4 u
= 8 u
8 u = 24
1 u = 24 ÷ 8 = 3
Number of jelly beans that Jade had at first
= 12 u
= 12 x 3
= 36
Answer(s): 36
