Nicole had 70 more chocolate bars than Opal. Nicole used
67 of her chocolate bars and Opal used
34 of her chocolate bars. In the end, Nicole had 2 times as much as Opal. Find the number of chocolate bars that Opal had at first.
|
Nicole |
Opal |
Comparing Nicole and Parry at first |
70 more |
|
Before |
7x2 = 14 u |
4 u |
Change |
- 6x2 = - 12 u |
- 3 u |
After |
1x2 = 2 u |
1 u |
Comparing Nicole and Parry in the end |
2 u |
1 u |
The number of chocolate bars that Nicole had in the end is repeated. Make the number of chocolate bars that Nicole had in the end the same. LCM of 1 and 2 is 2.
Number of chocolate bars that Nicole had more than Opal
= 14 u - 4 u
= 10 u
10 u = 70
1 u = 70 ÷ 10 = 7
Number of chocolate bars that Opal had at first
= 4 u
= 4 x 7
= 28
Answer(s): 28