Natalie had 48 less jelly beans than Kimberly. Kimberly used
34 of her jelly beans and Natalie used
34 of her jelly beans. In the end, Kimberly had 3 times as much as Natalie. Find the number of jelly beans that Kimberly had at first.
| |
Kimberly |
Natalie |
Comparing Kimberly
and Parry at first |
|
48 less |
| Before |
4x3 =
12 u |
4 u |
| Change |
- 3x3 =
- 9 u |
- 3 u |
| After |
1x3 =
3 u |
1 u |
Comparing Kimberly
and Parry in the end |
3 u |
1 u |
The number of jelly beans that Kimberly had in the end is repeated. Make the number of jelly beans that Kimberly had in the end the same. LCM of 1 and 3 is 3.
Number of jelly beans that Natalie had less than Kimberly
= 12 u - 4 u
= 8 u
8 u = 48
1 u = 48 ÷ 8 = 6
Number of jelly beans that Kimberly had at first
= 12 u
= 12 x 6
= 72
Answer(s): 72
