Kimberly had 84 less chocolate bars than Xuan. Xuan used
34 of her chocolate bars and Kimberly used
34 of her chocolate bars. In the end, Xuan had 4 times as much as Kimberly. Find the number of chocolate bars that Xuan had at first.
| |
Xuan |
Kimberly |
Comparing Xuan
and Parry at first |
|
84 less |
| Before |
4x4 =
16 u |
4 u |
| Change |
- 3x4 =
- 12 u |
- 3 u |
| After |
1x4 =
4 u |
1 u |
Comparing Xuan
and Parry in the end |
4 u |
1 u |
The number of chocolate bars that Xuan had in the end is repeated. Make the number of chocolate bars that Xuan had in the end the same. LCM of 1 and 4 is 4.
Number of chocolate bars that Kimberly had less than Xuan
= 16 u - 4 u
= 12 u
12 u = 84
1 u = 84 ÷ 12 = 7
Number of chocolate bars that Xuan had at first
= 16 u
= 16 x 7
= 112
Answer(s): 112
