Jane had 99 more jelly beans than Kathy. Jane used
34 of her jelly beans and Kathy used
45 of her jelly beans. In the end, Jane had 4 times as much as Kathy. Find the number of jelly beans that Kathy had at first.
| |
Jane |
Kathy |
Comparing Jane
and Parry at first |
99 more |
|
| Before |
4x4 =
16 u |
5 u |
| Change |
- 3x4 =
- 12 u |
- 4 u |
| After |
1x4 =
4 u |
1 u |
Comparing Jane
and Parry in the end |
4 u |
1 u |
The number of jelly beans that Jane had in the end is repeated. Make the number of jelly beans that Jane had in the end the same. LCM of 1 and 4 is 4.
Number of jelly beans that Jane had more than Kathy
= 16 u - 5 u
= 11 u
11 u = 99
1 u = 99 ÷ 11 = 9
Number of jelly beans that Kathy had at first
= 5 u
= 5 x 9
= 45
Answer(s): 45
