Marion had 96 more sweets than Xuan. Marion used
67 of her sweets and Xuan used
45 of her sweets. In the end, Marion had 3 times as much as Xuan. Find the number of sweets that Xuan had at first.
| |
Marion |
Xuan |
Comparing Marion
and Parry at first |
96 more |
|
| Before |
7x3 =
21 u |
5 u |
| Change |
- 6x3 =
- 18 u |
- 4 u |
| After |
1x3 =
3 u |
1 u |
Comparing Marion
and Parry in the end |
3 u |
1 u |
The number of sweets that Marion had in the end is repeated. Make the number of sweets that Marion had in the end the same. LCM of 1 and 3 is 3.
Number of sweets that Marion had more than Xuan
= 21 u - 5 u
= 16 u
16 u = 96
1 u = 96 ÷ 16 = 6
Number of sweets that Xuan had at first
= 5 u
= 5 x 6
= 30
Answer(s): 30
