Vanessa had 44 less jelly beans than Min. Min used
67 of her jelly beans and Vanessa used
23 of her jelly beans. In the end, Min had 2 times as much as Vanessa. Find the number of jelly beans that Min had at first.
| |
Min |
Vanessa |
Comparing Min
and Parry at first |
|
44 less |
| Before |
7x2 =
14 u |
3 u |
| Change |
- 6x2 =
- 12 u |
- 2 u |
| After |
1x2 =
2 u |
1 u |
Comparing Min
and Parry in the end |
2 u |
1 u |
The number of jelly beans that Min had in the end is repeated. Make the number of jelly beans that Min had in the end the same. LCM of 1 and 2 is 2.
Number of jelly beans that Vanessa had less than Min
= 14 u - 3 u
= 11 u
11 u = 44
1 u = 44 ÷ 11 = 4
Number of jelly beans that Min had at first
= 14 u
= 14 x 4
= 56
Answer(s): 56
