Xylia had 150 less chocolate bars than Joelle. Joelle used
45 of her chocolate bars and Xylia used
45 of her chocolate bars. In the end, Joelle had 4 times as much as Xylia. Find the number of chocolate bars that Joelle had at first.
| |
Joelle |
Xylia |
Comparing Joelle
and Parry at first |
|
150 less |
| Before |
5x4 =
20 u |
5 u |
| Change |
- 4x4 =
- 16 u |
- 4 u |
| After |
1x4 =
4 u |
1 u |
Comparing Joelle
and Parry in the end |
4 u |
1 u |
The number of chocolate bars that Joelle had in the end is repeated. Make the number of chocolate bars that Joelle had in the end the same. LCM of 1 and 4 is 4.
Number of chocolate bars that Xylia had less than Joelle
= 20 u - 5 u
= 15 u
15 u = 150
1 u = 150 ÷ 15 = 10
Number of chocolate bars that Joelle had at first
= 20 u
= 20 x 10
= 200
Answer(s): 200
