Cathy had 56 less sweets than Jaslyn. Jaslyn used
34 of her sweets and Cathy used
34 of her sweets. In the end, Jaslyn had 3 times as much as Cathy. Find the number of sweets that Jaslyn had at first.
|
Jaslyn |
Cathy |
Comparing Jaslyn and Parry at first |
|
56 less |
Before |
4x3 = 12 u |
4 u |
Change |
- 3x3 = - 9 u |
- 3 u |
After |
1x3 = 3 u |
1 u |
Comparing Jaslyn and Parry in the end |
3 u |
1 u |
The number of sweets that Jaslyn had in the end is repeated. Make the number of sweets that Jaslyn had in the end the same. LCM of 1 and 3 is 3.
Number of sweets that Cathy had less than Jaslyn
= 12 u - 4 u
= 8 u
8 u = 56
1 u = 56 ÷ 8 = 7
Number of sweets that Jaslyn had at first
= 12 u
= 12 x 7
= 84
Answer(s): 84