Raeann had 20 less jelly beans than Tammy. Tammy used
67 of her jelly beans and Raeann used
34 of her jelly beans. In the end, Tammy had 2 times as much as Raeann. Find the number of jelly beans that Tammy had at first.
| |
Tammy |
Raeann |
Comparing Tammy
and Parry at first |
|
20 less |
| Before |
7x2 =
14 u |
4 u |
| Change |
- 6x2 =
- 12 u |
- 3 u |
| After |
1x2 =
2 u |
1 u |
Comparing Tammy
and Parry in the end |
2 u |
1 u |
The number of jelly beans that Tammy had in the end is repeated. Make the number of jelly beans that Tammy had in the end the same. LCM of 1 and 2 is 2.
Number of jelly beans that Raeann had less than Tammy
= 14 u - 4 u
= 10 u
10 u = 20
1 u = 20 ÷ 10 = 2
Number of jelly beans that Tammy had at first
= 14 u
= 14 x 2
= 28
Answer(s): 28
