Wendy had 25 less jelly beans than Min. Min used
45 of her jelly beans and Wendy used
45 of her jelly beans. In the end, Min had 2 times as much as Wendy. Find the number of jelly beans that Min had at first.
| |
Min |
Wendy |
Comparing Min
and Parry at first |
|
25 less |
| Before |
5x2 =
10 u |
5 u |
| Change |
- 4x2 =
- 8 u |
- 4 u |
| After |
1x2 =
2 u |
1 u |
Comparing Min
and Parry in the end |
2 u |
1 u |
The number of jelly beans that Min had in the end is repeated. Make the number of jelly beans that Min had in the end the same. LCM of 1 and 2 is 2.
Number of jelly beans that Wendy had less than Min
= 10 u - 5 u
= 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Number of jelly beans that Min had at first
= 10 u
= 10 x 5
= 50
Answer(s): 50
