Opal had 144 less chocolate bars than Betty. Betty used
67 of her chocolate bars and Opal used
45 of her chocolate bars. In the end, Betty had 3 times as much as Opal. Find the number of chocolate bars that Betty had at first.
|
Betty |
Opal |
Comparing Betty and Parry at first |
|
144 less |
Before |
7x3 = 21 u |
5 u |
Change |
- 6x3 = - 18 u |
- 4 u |
After |
1x3 = 3 u |
1 u |
Comparing Betty and Parry in the end |
3 u |
1 u |
The number of chocolate bars that Betty had in the end is repeated. Make the number of chocolate bars that Betty had in the end the same. LCM of 1 and 3 is 3.
Number of chocolate bars that Opal had less than Betty
= 21 u - 5 u
= 16 u
16 u = 144
1 u = 144 ÷ 16 = 9
Number of chocolate bars that Betty had at first
= 21 u
= 21 x 9
= 189
Answer(s): 189