Sabrina had 50 less sweets than Yen. Yen used
45 of her sweets and Sabrina used
45 of her sweets. In the end, Yen had 2 times as much as Sabrina. Find the number of sweets that Yen had at first.
| |
Yen |
Sabrina |
Comparing Yen
and Parry at first |
|
50 less |
| Before |
5x2 =
10 u |
5 u |
| Change |
- 4x2 =
- 8 u |
- 4 u |
| After |
1x2 =
2 u |
1 u |
Comparing Yen
and Parry in the end |
2 u |
1 u |
The number of sweets that Yen had in the end is repeated. Make the number of sweets that Yen had in the end the same. LCM of 1 and 2 is 2.
Number of sweets that Sabrina had less than Yen
= 10 u - 5 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Number of sweets that Yen had at first
= 10 u
= 10 x 10
= 100
Answer(s): 100
