Min had 45 less lollipops than Abi. Abi used
56 of her lollipops and Min used
23 of her lollipops. In the end, Abi had 2 times as much as Min. Find the number of lollipops that Abi had at first.
| |
Abi |
Min |
Comparing Abi
and Parry at first |
|
45 less |
| Before |
6x2 =
12 u |
3 u |
| Change |
- 5x2 =
- 10 u |
- 2 u |
| After |
1x2 =
2 u |
1 u |
Comparing Abi
and Parry in the end |
2 u |
1 u |
The number of lollipops that Abi had in the end is repeated. Make the number of lollipops that Abi had in the end the same. LCM of 1 and 2 is 2.
Number of lollipops that Min had less than Abi
= 12 u - 3 u
= 9 u
9 u = 45
1 u = 45 ÷ 9 = 5
Number of lollipops that Abi had at first
= 12 u
= 12 x 5
= 60
Answer(s): 60
