Eva had 10 less jelly beans than Ivory. Ivory used
45 of her jelly beans and Eva used
45 of her jelly beans. In the end, Ivory had 2 times as much as Eva. Find the number of jelly beans that Ivory had at first.
|
Ivory |
Eva |
Comparing Ivory and Parry at first |
|
10 less |
Before |
5x2 = 10 u |
5 u |
Change |
- 4x2 = - 8 u |
- 4 u |
After |
1x2 = 2 u |
1 u |
Comparing Ivory and Parry in the end |
2 u |
1 u |
The number of jelly beans that Ivory had in the end is repeated. Make the number of jelly beans that Ivory had in the end the same. LCM of 1 and 2 is 2.
Number of jelly beans that Eva had less than Ivory
= 10 u - 5 u
= 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Number of jelly beans that Ivory had at first
= 10 u
= 10 x 2
= 20
Answer(s): 20