Hazel had 40 less candy canes than Jaslyn. Jaslyn used
67 of her candy canes and Hazel used
34 of her candy canes. In the end, Jaslyn had 2 times as much as Hazel. Find the number of candy canes that Jaslyn had at first.
| |
Jaslyn |
Hazel |
Comparing Jaslyn
and Parry at first |
|
40 less |
| Before |
7x2 =
14 u |
4 u |
| Change |
- 6x2 =
- 12 u |
- 3 u |
| After |
1x2 =
2 u |
1 u |
Comparing Jaslyn
and Parry in the end |
2 u |
1 u |
The number of candy canes that Jaslyn had in the end is repeated. Make the number of candy canes that Jaslyn had in the end the same. LCM of 1 and 2 is 2.
Number of candy canes that Hazel had less than Jaslyn
= 14 u - 4 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Number of candy canes that Jaslyn had at first
= 14 u
= 14 x 4
= 56
Answer(s): 56
