Jean had 12 more candy canes than Jade. Jean used
34 of her candy canes and Jade used
45 of her candy canes. In the end, Jean had 2 times as much as Jade. Find the number of candy canes that Jade had at first.
| |
Jean |
Jade |
Comparing Jean
and Parry at first |
12 more |
|
| Before |
4x2 =
8 u |
5 u |
| Change |
- 3x2 =
- 6 u |
- 4 u |
| After |
1x2 =
2 u |
1 u |
Comparing Jean
and Parry in the end |
2 u |
1 u |
The number of candy canes that Jean had in the end is repeated. Make the number of candy canes that Jean had in the end the same. LCM of 1 and 2 is 2.
Number of candy canes that Jean had more than Jade
= 8 u - 5 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of candy canes that Jade had at first
= 5 u
= 5 x 4
= 20
Answer(s): 20
