Jane had 72 less chocolate bars than Opal. Opal used
78 of her chocolate bars and Jane used
34 of her chocolate bars. In the end, Opal had 2 times as much as Jane. Find the number of chocolate bars that Opal had at first.
|
Opal |
Jane |
Comparing Opal and Parry at first |
|
72 less |
Before |
8x2 = 16 u |
4 u |
Change |
- 7x2 = - 14 u |
- 3 u |
After |
1x2 = 2 u |
1 u |
Comparing Opal and Parry in the end |
2 u |
1 u |
The number of chocolate bars that Opal had in the end is repeated. Make the number of chocolate bars that Opal had in the end the same. LCM of 1 and 2 is 2.
Number of chocolate bars that Jane had less than Opal
= 16 u - 4 u
= 12 u
12 u = 72
1 u = 72 ÷ 12 = 6
Number of chocolate bars that Opal had at first
= 16 u
= 16 x 6
= 96
Answer(s): 96