Opal had 90 less sweets than Cathy. Cathy used
67 of her sweets and Opal used
45 of her sweets. In the end, Cathy had 2 times as much as Opal. Find the number of sweets that Cathy had at first.
| |
Cathy |
Opal |
Comparing Cathy
and Parry at first |
|
90 less |
| Before |
7x2 =
14 u |
5 u |
| Change |
- 6x2 =
- 12 u |
- 4 u |
| After |
1x2 =
2 u |
1 u |
Comparing Cathy
and Parry in the end |
2 u |
1 u |
The number of sweets that Cathy had in the end is repeated. Make the number of sweets that Cathy had in the end the same. LCM of 1 and 2 is 2.
Number of sweets that Opal had less than Cathy
= 14 u - 5 u
= 9 u
9 u = 90
1 u = 90 ÷ 9 = 10
Number of sweets that Cathy had at first
= 14 u
= 14 x 10
= 140
Answer(s): 140
