Wendy had 40 less jelly beans than Xylia. Xylia used
67 of her jelly beans and Wendy used
34 of her jelly beans. In the end, Xylia had 2 times as much as Wendy. Find the number of jelly beans that Xylia had at first.
| |
Xylia |
Wendy |
Comparing Xylia
and Parry at first |
|
40 less |
| Before |
7x2 =
14 u |
4 u |
| Change |
- 6x2 =
- 12 u |
- 3 u |
| After |
1x2 =
2 u |
1 u |
Comparing Xylia
and Parry in the end |
2 u |
1 u |
The number of jelly beans that Xylia had in the end is repeated. Make the number of jelly beans that Xylia had in the end the same. LCM of 1 and 2 is 2.
Number of jelly beans that Wendy had less than Xylia
= 14 u - 4 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Number of jelly beans that Xylia had at first
= 14 u
= 14 x 4
= 56
Answer(s): 56
