Shannon had 72 less sweets than Joelle. Joelle used
34 of her sweets and Shannon used
34 of her sweets. In the end, Joelle had 3 times as much as Shannon. Find the number of sweets that Joelle had at first.
| |
Joelle |
Shannon |
Comparing Joelle
and Parry at first |
|
72 less |
| Before |
4x3 =
12 u |
4 u |
| Change |
- 3x3 =
- 9 u |
- 3 u |
| After |
1x3 =
3 u |
1 u |
Comparing Joelle
and Parry in the end |
3 u |
1 u |
The number of sweets that Joelle had in the end is repeated. Make the number of sweets that Joelle had in the end the same. LCM of 1 and 3 is 3.
Number of sweets that Shannon had less than Joelle
= 12 u - 4 u
= 8 u
8 u = 72
1 u = 72 ÷ 8 = 9
Number of sweets that Joelle had at first
= 12 u
= 12 x 9
= 108
Answer(s): 108
