Kimberly had 108 less jelly beans than Penelope. Penelope used
56 of her jelly beans and Kimberly used
23 of her jelly beans. In the end, Penelope had 2 times as much as Kimberly. Find the number of jelly beans that Penelope had at first.
| |
Penelope |
Kimberly |
Comparing Penelope
and Parry at first |
|
108 less |
| Before |
6x2 =
12 u |
3 u |
| Change |
- 5x2 =
- 10 u |
- 2 u |
| After |
1x2 =
2 u |
1 u |
Comparing Penelope
and Parry in the end |
2 u |
1 u |
The number of jelly beans that Penelope had in the end is repeated. Make the number of jelly beans that Penelope had in the end the same. LCM of 1 and 2 is 2.
Number of jelly beans that Kimberly had less than Penelope
= 12 u - 3 u
= 9 u
9 u = 108
1 u = 108 ÷ 9 = 12
Number of jelly beans that Penelope had at first
= 12 u
= 12 x 12
= 144
Answer(s): 144
