Marion had 96 more chocolate bars than Mary. Marion used
78 of her chocolate bars and Mary used
34 of her chocolate bars. In the end, Marion had 2 times as much as Mary. Find the number of chocolate bars that Mary had at first.
| |
Marion |
Mary |
Comparing Marion
and Parry at first |
96 more |
|
| Before |
8x2 =
16 u |
4 u |
| Change |
- 7x2 =
- 14 u |
- 3 u |
| After |
1x2 =
2 u |
1 u |
Comparing Marion
and Parry in the end |
2 u |
1 u |
The number of chocolate bars that Marion had in the end is repeated. Make the number of chocolate bars that Marion had in the end the same. LCM of 1 and 2 is 2.
Number of chocolate bars that Marion had more than Mary
= 16 u - 4 u
= 12 u
12 u = 96
1 u = 96 ÷ 12 = 8
Number of chocolate bars that Mary had at first
= 4 u
= 4 x 8
= 32
Answer(s): 32
