Winnie had 70 less sweets than Tina. Tina used
56 of her sweets and Winnie used
12 of her sweets. In the end, Tina had 2 times as much as Winnie. Find the number of sweets that Tina had at first.
| |
Tina |
Winnie |
Comparing Tina
and Parry at first |
|
70 less |
| Before |
6x2 =
12 u |
2 u |
| Change |
- 5x2 =
- 10 u |
- 1 u |
| After |
1x2 =
2 u |
1 u |
Comparing Tina
and Parry in the end |
2 u |
1 u |
The number of sweets that Tina had in the end is repeated. Make the number of sweets that Tina had in the end the same. LCM of 1 and 2 is 2.
Number of sweets that Winnie had less than Tina
= 12 u - 2 u
= 10 u
10 u = 70
1 u = 70 ÷ 10 = 7
Number of sweets that Tina had at first
= 12 u
= 12 x 7
= 84
Answer(s): 84
