Cindy had 90 less jelly beans than Kylie. Kylie used
34 of her jelly beans and Cindy used
23 of her jelly beans. In the end, Kylie had 3 times as much as Cindy. Find the number of jelly beans that Kylie had at first.
| |
Kylie |
Cindy |
Comparing Kylie
and Parry at first |
|
90 less |
| Before |
4x3 =
12 u |
3 u |
| Change |
- 3x3 =
- 9 u |
- 2 u |
| After |
1x3 =
3 u |
1 u |
Comparing Kylie
and Parry in the end |
3 u |
1 u |
The number of jelly beans that Kylie had in the end is repeated. Make the number of jelly beans that Kylie had in the end the same. LCM of 1 and 3 is 3.
Number of jelly beans that Cindy had less than Kylie
= 12 u - 3 u
= 9 u
9 u = 90
1 u = 90 ÷ 9 = 10
Number of jelly beans that Kylie had at first
= 12 u
= 12 x 10
= 120
Answer(s): 120
