Opal had 96 less sweets than Cindy. Cindy used
78 of her sweets and Opal used
34 of her sweets. In the end, Cindy had 2 times as much as Opal. Find the number of sweets that Cindy had at first.
| |
Cindy |
Opal |
Comparing Cindy
and Parry at first |
|
96 less |
| Before |
8x2 =
16 u |
4 u |
| Change |
- 7x2 =
- 14 u |
- 3 u |
| After |
1x2 =
2 u |
1 u |
Comparing Cindy
and Parry in the end |
2 u |
1 u |
The number of sweets that Cindy had in the end is repeated. Make the number of sweets that Cindy had in the end the same. LCM of 1 and 2 is 2.
Number of sweets that Opal had less than Cindy
= 16 u - 4 u
= 12 u
12 u = 96
1 u = 96 ÷ 12 = 8
Number of sweets that Cindy had at first
= 16 u
= 16 x 8
= 128
Answer(s): 128
