Abi had 66 less chocolate bars than Shannon. Shannon used
34 of her chocolate bars and Abi used
12 of her chocolate bars. In the end, Shannon had 2 times as much as Abi. Find the number of chocolate bars that Shannon had at first.
| |
Shannon |
Abi |
Comparing Shannon
and Parry at first |
|
66 less |
| Before |
4x2 =
8 u |
2 u |
| Change |
- 3x2 =
- 6 u |
- 1 u |
| After |
1x2 =
2 u |
1 u |
Comparing Shannon
and Parry in the end |
2 u |
1 u |
The number of chocolate bars that Shannon had in the end is repeated. Make the number of chocolate bars that Shannon had in the end the same. LCM of 1 and 2 is 2.
Number of chocolate bars that Abi had less than Shannon
= 8 u - 2 u
= 6 u
6 u = 66
1 u = 66 ÷ 6 = 11
Number of chocolate bars that Shannon had at first
= 8 u
= 8 x 11
= 88
Answer(s): 88
