Opal had 144 less candy canes than Gem. Gem used
67 of her candy canes and Opal used
45 of her candy canes. In the end, Gem had 3 times as much as Opal. Find the number of candy canes that Gem had at first.
| |
Gem |
Opal |
Comparing Gem
and Parry at first |
|
144 less |
| Before |
7x3 =
21 u |
5 u |
| Change |
- 6x3 =
- 18 u |
- 4 u |
| After |
1x3 =
3 u |
1 u |
Comparing Gem
and Parry in the end |
3 u |
1 u |
The number of candy canes that Gem had in the end is repeated. Make the number of candy canes that Gem had in the end the same. LCM of 1 and 3 is 3.
Number of candy canes that Opal had less than Gem
= 21 u - 5 u
= 16 u
16 u = 144
1 u = 144 ÷ 16 = 9
Number of candy canes that Gem had at first
= 21 u
= 21 x 9
= 189
Answer(s): 189
