Tim had $190 less than Dylan. If Dylan spends $160 and Tim's mother gave Tim $500, Dylan will have
16 as much money as Tim. How much money did Tim and Dylan have?
| |
Make p the same
(1)x6 = (3) |
Tim
(1) |
Dylan
(2) |
| Before |
6 u |
1 u |
1 u + 190 |
| Change |
- 960 |
- 160 |
+ 500 |
| After |
6 p |
1 p |
6 p |
Since Tim had $190 less than Dylan, this means Dylan had $190 more than Tim.
1 u - 160 = 1 p --- (1)
1 u + 190 + 500 = 6 p
1 u + 690 =
6 p --- (2)
Make p the same.
(1)
x6
6 u - 960 =
6 p --- (3)
(3) = (2)
6 u - 960 = 1 u + 690
6 u - 1 u = 690 + 960
5 u = 1650
1 u = 1650 ÷ 5 = 330
Total amount that Tim and Dylan had
= 1 u + 1 u + 190
= 2 u + 190
= 2 x 330 + 190
= 660 + 190
= $850
Answer(s): $850
