Eva will be 64 years old in 12 years' time. Now, Hazel's age is 34 of Eva's age. What was Hazel's age when she was 3 years less than 90% of Eva's age?
| |
Hazel |
Eva |
Difference |
| Before |
9 p - 3 |
10 p |
1 p + 3 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
3 u |
4 u |
1 u |
| Change 2 |
+ 12 |
+ 12 |
|
| After |
3 u + 12 |
64 |
|
Eva's age in 12 years' time = 4 u + 12
4 u + 12 = 64
4 u = 64 - 12
4 u = 52
1 u = 52 ÷ 4 = 13
Difference between Eva's age and Hazel's age
= 1 u
= 13
90% =
90100 =
910 Difference in Eva's age and Hazel's age at first
= 10 p - (9 p - 3)
= 1 p + 3
The difference in age between Eva and Hazel remains unchanged.
1 p + 3 = 13
1 p = 13 - 3 = 10
Hazel's age when she was 3 years less than 90% of Eva's age
= 9 p - 3
= 9 x 10 - 3
= 90 - 3
= 87
Answer(s): 87
