Wendy will be 35 years old in 8 years' time. Now, Jaslyn's age is 23 of Wendy's age. What was Jaslyn's age when she was 4 years less than 80% of Wendy's age?
| |
Jaslyn |
Wendy |
Difference |
| Before |
4 p - 4 |
5 p |
1 p + 4 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
2 u |
3 u |
1 u |
| Change 2 |
+ 8 |
+ 8 |
|
| After |
2 u + 8 |
35 |
|
Wendy's age in 8 years' time = 3 u + 8
3 u + 8 = 35
3 u = 35 - 8
3 u = 27
1 u = 27 ÷ 3 = 9
Difference between Wendy's age and Jaslyn's age
= 1 u
= 9
80% =
80100 =
45 Difference in Wendy's age and Jaslyn's age at first
= 5 p - (4 p - 4)
= 1 p + 4
The difference in age between Wendy and Jaslyn remains unchanged.
1 p + 4 = 9
1 p = 9 - 4 = 5
Jaslyn's age when she was 4 years less than 80% of Wendy's age
= 4 p - 4
= 4 x 5 - 4
= 20 - 4
= 16
Answer(s): 16
