Hazel will be 38 years old in 8 years' time. Now, Sabrina's age is 56 of Hazel's age. What was Sabrina's age when she was 2 years more than 75% of Hazel's age?
| |
Sabrina |
Hazel |
Difference |
| Before |
3 p + 2 |
4 p |
1 p - 2 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
5 u |
6 u |
1 u |
| Change 2 |
+ 8 |
+ 8 |
|
| After |
5 u + 8 |
38 |
|
Hazel's age in 8 years' time = 6 u + 8
6 u + 8 = 38
6 u = 38 - 8
6 u = 30
1 u = 30 ÷ 6 = 5
Difference between Hazel's age and Sabrina's age
= 1 u
= 5
75% =
75100 =
34 Difference in Hazel's age and Sabrina's age at first
= 4 p - (3 p + 2)
= 1 p - 2
The difference in age between Hazel and Sabrina remains unchanged.
1 p - 2 = 5
1 p = 5 + 2 = 7
Sabrina's age when she was 2 years more than 75% of Hazel's age
= 3 p + 2
= 3 x 7 + 2
= 21 + 2
= 23
Answer(s): 23
