Gabby will be 72 years old in 18 years' time. Now, Lynn's age is 56 of Gabby's age. What was Lynn's age when she was 3 years more than 75% of Gabby's age?
| |
Lynn |
Gabby |
Difference |
| Before |
3 p + 3 |
4 p |
1 p - 3 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
5 u |
6 u |
1 u |
| Change 2 |
+ 18 |
+ 18 |
|
| After |
5 u + 18 |
72 |
|
Gabby's age in 18 years' time = 6 u + 18
6 u + 18 = 72
6 u = 72 - 18
6 u = 54
1 u = 54 ÷ 6 = 9
Difference between Gabby's age and Lynn's age
= 1 u
= 9
75% =
75100 =
34 Difference in Gabby's age and Lynn's age at first
= 4 p - (3 p + 3)
= 1 p - 3
The difference in age between Gabby and Lynn remains unchanged.
1 p - 3 = 9
1 p = 9 + 3 = 12
Lynn's age when she was 3 years more than 75% of Gabby's age
= 3 p + 3
= 3 x 12 + 3
= 36 + 3
= 39
Answer(s): 39
