Winnie will be 37 years old in 9 years' time. Now, Esther's age is 12 of Winnie's age. What was Esther's age when she was 2 years less than 80% of Winnie's age?
| |
Esther |
Winnie |
Difference |
| Before |
4 p - 2 |
5 p |
1 p + 2 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
1 u |
2 u |
1 u |
| Change 2 |
+ 9 |
+ 9 |
|
| After |
1 u + 9 |
37 |
|
Winnie's age in 9 years' time = 2 u + 9
2 u + 9 = 37
2 u = 37 - 9
2 u = 28
1 u = 28 ÷ 2 = 14
Difference between Winnie's age and Esther's age
= 1 u
= 14
80% =
80100 =
45 Difference in Winnie's age and Esther's age at first
= 5 p - (4 p - 2)
= 1 p + 2
The difference in age between Winnie and Esther remains unchanged.
1 p + 2 = 14
1 p = 14 - 2 = 12
Esther's age when she was 2 years less than 80% of Winnie's age
= 4 p - 2
= 4 x 12 - 2
= 48 - 2
= 46
Answer(s): 46
