Linda will be 58 years old in 10 years' time. Now, Cindy's age is 56 of Linda's age. What was Cindy's age when she was 3 years more than 75% of Linda's age?
| |
Cindy |
Linda |
Difference |
| Before |
3 p + 3 |
4 p |
1 p - 3 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
5 u |
6 u |
1 u |
| Change 2 |
+ 10 |
+ 10 |
|
| After |
5 u + 10 |
58 |
|
Linda's age in 10 years' time = 6 u + 10
6 u + 10 = 58
6 u = 58 - 10
6 u = 48
1 u = 48 ÷ 6 = 8
Difference between Linda's age and Cindy's age
= 1 u
= 8
75% =
75100 =
34 Difference in Linda's age and Cindy's age at first
= 4 p - (3 p + 3)
= 1 p - 3
The difference in age between Linda and Cindy remains unchanged.
1 p - 3 = 8
1 p = 8 + 3 = 11
Cindy's age when she was 3 years more than 75% of Linda's age
= 3 p + 3
= 3 x 11 + 3
= 33 + 3
= 36
Answer(s): 36
