Min will be 56 years old in 6 years' time. Now, Fiona's age is 45 of Min's age. What was Fiona's age when she was 2 years more than 75% of Min's age?
| |
Fiona |
Min |
Difference |
| Before |
3 p + 2 |
4 p |
1 p - 2 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
4 u |
5 u |
1 u |
| Change 2 |
+ 6 |
+ 6 |
|
| After |
4 u + 6 |
56 |
|
Min's age in 6 years' time = 5 u + 6
5 u + 6 = 56
5 u = 56 - 6
5 u = 50
1 u = 50 ÷ 5 = 10
Difference between Min's age and Fiona's age
= 1 u
= 10
75% =
75100 =
34 Difference in Min's age and Fiona's age at first
= 4 p - (3 p + 2)
= 1 p - 2
The difference in age between Min and Fiona remains unchanged.
1 p - 2 = 10
1 p = 10 + 2 = 12
Fiona's age when she was 2 years more than 75% of Min's age
= 3 p + 2
= 3 x 12 + 2
= 36 + 2
= 38
Answer(s): 38
