Dana will be 84 years old in 19 years' time. Now, Jean's age is 45 of Dana's age. What was Jean's age when she was 3 years more than 75% of Dana's age?
| |
Jean |
Dana |
Difference |
| Before |
3 p + 3 |
4 p |
1 p - 3 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
4 u |
5 u |
1 u |
| Change 2 |
+ 19 |
+ 19 |
|
| After |
4 u + 19 |
84 |
|
Dana's age in 19 years' time = 5 u + 19
5 u + 19 = 84
5 u = 84 - 19
5 u = 65
1 u = 65 ÷ 5 = 13
Difference between Dana's age and Jean's age
= 1 u
= 13
75% =
75100 =
34 Difference in Dana's age and Jean's age at first
= 4 p - (3 p + 3)
= 1 p - 3
The difference in age between Dana and Jean remains unchanged.
1 p - 3 = 13
1 p = 13 + 3 = 16
Jean's age when she was 3 years more than 75% of Dana's age
= 3 p + 3
= 3 x 16 + 3
= 48 + 3
= 51
Answer(s): 51
