Cathy will be 68 years old in 16 years' time. Now, Hilda's age is 34 of Cathy's age. What was Hilda's age when she was 6 years less than 75% of Cathy's age?
| |
Hilda |
Cathy |
Difference |
| Before |
3 p - 6 |
4 p |
1 p + 6 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
3 u |
4 u |
1 u |
| Change 2 |
+ 16 |
+ 16 |
|
| After |
3 u + 16 |
68 |
|
Cathy's age in 16 years' time = 4 u + 16
4 u + 16 = 68
4 u = 68 - 16
4 u = 52
1 u = 52 ÷ 4 = 13
Difference between Cathy's age and Hilda's age
= 1 u
= 13
75% =
75100 =
34 Difference in Cathy's age and Hilda's age at first
= 4 p - (3 p - 6)
= 1 p + 6
The difference in age between Cathy and Hilda remains unchanged.
1 p + 6 = 13
1 p = 13 - 6 = 7
Hilda's age when she was 6 years less than 75% of Cathy's age
= 3 p - 6
= 3 x 7 - 6
= 21 - 6
= 15
Answer(s): 15
