Jaslyn will be 45 years old in 6 years' time. Now, Betty's age is 23 of Jaslyn's age. What was Betty's age when she was 5 years less than 75% of Jaslyn's age?
| |
Betty |
Jaslyn |
Difference |
| Before |
3 p - 5 |
4 p |
1 p + 5 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
2 u |
3 u |
1 u |
| Change 2 |
+ 6 |
+ 6 |
|
| After |
2 u + 6 |
45 |
|
Jaslyn's age in 6 years' time = 3 u + 6
3 u + 6 = 45
3 u = 45 - 6
3 u = 39
1 u = 39 ÷ 3 = 13
Difference between Jaslyn's age and Betty's age
= 1 u
= 13
75% =
75100 =
34 Difference in Jaslyn's age and Betty's age at first
= 4 p - (3 p - 5)
= 1 p + 5
The difference in age between Jaslyn and Betty remains unchanged.
1 p + 5 = 13
1 p = 13 - 5 = 8
Betty's age when she was 5 years less than 75% of Jaslyn's age
= 3 p - 5
= 3 x 8 - 5
= 24 - 5
= 19
Answer(s): 19
