Xylia will be 31 years old in 13 years' time. Now, Lucy's age is 12 of Xylia's age. What was Lucy's age when she was 2 years less than 80% of Xylia's age?
| |
Lucy |
Xylia |
Difference |
| Before |
4 p - 2 |
5 p |
1 p + 2 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
1 u |
2 u |
1 u |
| Change 2 |
+ 13 |
+ 13 |
|
| After |
1 u + 13 |
31 |
|
Xylia's age in 13 years' time = 2 u + 13
2 u + 13 = 31
2 u = 31 - 13
2 u = 18
1 u = 18 ÷ 2 = 9
Difference between Xylia's age and Lucy's age
= 1 u
= 9
80% =
80100 =
45 Difference in Xylia's age and Lucy's age at first
= 5 p - (4 p - 2)
= 1 p + 2
The difference in age between Xylia and Lucy remains unchanged.
1 p + 2 = 9
1 p = 9 - 2 = 7
Lucy's age when she was 2 years less than 80% of Xylia's age
= 4 p - 2
= 4 x 7 - 2
= 28 - 2
= 26
Answer(s): 26
