Tina will be 73 years old in 19 years' time. Now, Elyse's age is 56 of Tina's age. What was Elyse's age when she was 4 years more than 75% of Tina's age?
| |
Elyse |
Tina |
Difference |
| Before |
3 p + 4 |
4 p |
1 p - 4 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
5 u |
6 u |
1 u |
| Change 2 |
+ 19 |
+ 19 |
|
| After |
5 u + 19 |
73 |
|
Tina's age in 19 years' time = 6 u + 19
6 u + 19 = 73
6 u = 73 - 19
6 u = 54
1 u = 54 ÷ 6 = 9
Difference between Tina's age and Elyse's age
= 1 u
= 9
75% =
75100 =
34 Difference in Tina's age and Elyse's age at first
= 4 p - (3 p + 4)
= 1 p - 4
The difference in age between Tina and Elyse remains unchanged.
1 p - 4 = 9
1 p = 9 + 4 = 13
Elyse's age when she was 4 years more than 75% of Tina's age
= 3 p + 4
= 3 x 13 + 4
= 39 + 4
= 43
Answer(s): 43
