Lucy will be 65 years old in 11 years' time. Now, Gabby's age is 56 of Lucy's age. What was Gabby's age when she was 4 years more than 75% of Lucy's age?
| |
Gabby |
Lucy |
Difference |
| Before |
3 p + 4 |
4 p |
1 p - 4 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
5 u |
6 u |
1 u |
| Change 2 |
+ 11 |
+ 11 |
|
| After |
5 u + 11 |
65 |
|
Lucy's age in 11 years' time = 6 u + 11
6 u + 11 = 65
6 u = 65 - 11
6 u = 54
1 u = 54 ÷ 6 = 9
Difference between Lucy's age and Gabby's age
= 1 u
= 9
75% =
75100 =
34 Difference in Lucy's age and Gabby's age at first
= 4 p - (3 p + 4)
= 1 p - 4
The difference in age between Lucy and Gabby remains unchanged.
1 p - 4 = 9
1 p = 9 + 4 = 13
Gabby's age when she was 4 years more than 75% of Lucy's age
= 3 p + 4
= 3 x 13 + 4
= 39 + 4
= 43
Answer(s): 43
