Abi will be 81 years old in 9 years' time. Now, Lynn's age is 56 of Abi's age. What was Lynn's age when she was 4 years more than 75% of Abi's age?
| |
Lynn |
Abi |
Difference |
| Before |
3 p + 4 |
4 p |
1 p - 4 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
5 u |
6 u |
1 u |
| Change 2 |
+ 9 |
+ 9 |
|
| After |
5 u + 9 |
81 |
|
Abi's age in 9 years' time = 6 u + 9
6 u + 9 = 81
6 u = 81 - 9
6 u = 72
1 u = 72 ÷ 6 = 12
Difference between Abi's age and Lynn's age
= 1 u
= 12
75% =
75100 =
34 Difference in Abi's age and Lynn's age at first
= 4 p - (3 p + 4)
= 1 p - 4
The difference in age between Abi and Lynn remains unchanged.
1 p - 4 = 12
1 p = 12 + 4 = 16
Lynn's age when she was 4 years more than 75% of Abi's age
= 3 p + 4
= 3 x 16 + 4
= 48 + 4
= 52
Answer(s): 52
