Winnie will be 75 years old in 19 years' time. Now, Irene's age is 34 of Winnie's age. What was Irene's age when she was 5 years less than 80% of Winnie's age?
| |
Irene |
Winnie |
Difference |
| Before |
4 p - 5 |
5 p |
1 p + 5 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
3 u |
4 u |
1 u |
| Change 2 |
+ 19 |
+ 19 |
|
| After |
3 u + 19 |
75 |
|
Winnie's age in 19 years' time = 4 u + 19
4 u + 19 = 75
4 u = 75 - 19
4 u = 56
1 u = 56 ÷ 4 = 14
Difference between Winnie's age and Irene's age
= 1 u
= 14
80% =
80100 =
45 Difference in Winnie's age and Irene's age at first
= 5 p - (4 p - 5)
= 1 p + 5
The difference in age between Winnie and Irene remains unchanged.
1 p + 5 = 14
1 p = 14 - 5 = 9
Irene's age when she was 5 years less than 80% of Winnie's age
= 4 p - 5
= 4 x 9 - 5
= 36 - 5
= 31
Answer(s): 31
