Xuan will be 51 years old in 6 years' time. Now, Abi's age is 45 of Xuan's age. What was Abi's age when she was 2 years more than 75% of Xuan's age?
| |
Abi |
Xuan |
Difference |
| Before |
3 p + 2 |
4 p |
1 p - 2 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
4 u |
5 u |
1 u |
| Change 2 |
+ 6 |
+ 6 |
|
| After |
4 u + 6 |
51 |
|
Xuan's age in 6 years' time = 5 u + 6
5 u + 6 = 51
5 u = 51 - 6
5 u = 45
1 u = 45 ÷ 5 = 9
Difference between Xuan's age and Abi's age
= 1 u
= 9
75% =
75100 =
34 Difference in Xuan's age and Abi's age at first
= 4 p - (3 p + 2)
= 1 p - 2
The difference in age between Xuan and Abi remains unchanged.
1 p - 2 = 9
1 p = 9 + 2 = 11
Abi's age when she was 2 years more than 75% of Xuan's age
= 3 p + 2
= 3 x 11 + 2
= 33 + 2
= 35
Answer(s): 35
